Answer to Question #246619 in Chemistry for abdulmajeed

Question

Given the following equation:            8 Fe + S₈ ---> 8 FeS

What mass of Fe is needed to react with 16.0 grams of sulfur (S₈)?

(Fe= 55.8, S=32)

 

Answer 1

M(Fe) = 55.8 g/mol

M(S₈) = 8 × M(S) = 8 × 32 = 256 g/mol

Solution:

Balanced chemical equation:

8Fe + S₈ ⟶ 8FeS

According to stoichiometry:

(16.0 g S₈) × (1 mol S₈ / 256 g S₈) × (8 mol Fe / 1 mol S₈) × (55.8 g Fe / 1 mol Fe) = 27.9 g Fe

Answer: 27.9 grams of Fe is needed to react with 16.0 grams of S₈