Answer to Question #246083 in Chemistry for Ali

Question

How to prepare 2M FeSO4 Solution

Answer 1

Solution:

Assume that you want to prepare 1 L of 2 M FeSO₄.

Step 1. Calculate the moles of FeSO₄ needed:

Moles of FeSO₄ = (1 L) × (2 mol FeSO₄ / 1 L) = 2 mol FeSO₄

Step 2. Calculate the mass of FeSO₄ needed:

The molar mass of FeSO₄ is 151.908 g/mol

Hence,

Mass of FeSO₄ = (2 mol FeSO₄) × (151.908 g FeSO₄ / 1 mol FeSO₄) = 303.816 g FeSO₄

Mass of FeSO₄ = 303.82 g FeSO₄

Answer: To make 1 L of 2 M FeSO₄, you take 303.82 g of FeSO₄ and add water to make a total of 1 L.