A solution of hydrochloric acid has a concentration of 4.50g L-1 .
(i) Calculate the hydronium ion concentration in mol L-1 .
(ii) Calculate the pH of the solution.
Solution:
hydrochloric acid = HCl
hydronium ion = H3O+
The molar mass of HCl is 36.458 g/mol
Hence,
(4.50 g HCl L-1) × (1 mol HCl / 36.458 g HCl) = 0.123 mol L-1
C(HCl) = 0.123 mol L-1
HCl(aq) + H2O(l) → H3O+(aq) + Cl-(aq)
HCl is a strong acid.
Hence,
[H3O+] = C(HCl) = 0.123 mol L-1
[H3O+] = 0.123 mol L-1
We can convert between [H3O+] and pH using the following equation:
pH = - log[H3O+]
pH = - log(0.123) = 0.91
pH = 0.91
Answers:
(i): [H3O+] = 0.123 mol L-1
(ii): pH = 0.91
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