How many sodium ions are in 3.0 moles of NaCI?
Solution:
NaCl → Na+ + Cl-
Hence,
n(Na+) = n(NaCl) = 3.0 mol
One mole of any substance contains 6.022×1023 particles.
Hence,
(3.0 mol Na+ ions) × (6.022×1023 Na+ ions / 1 mol Na+ ions) = 1.8×1024 Na+ ions
Answer: 1.8×1024 sodium ions are in 3.0 moles of NaCI.
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