Question

How many moles of S are present in 15.00616 mg of SO2 (sulfur dioxide).

Answer 1

How many moles of S are present in 15.00616 mg of SO2 (sulfur dioxide).

Solution:

As far as the number mole of $\mathrm{SO}_2$ equal the number mole of S, we find how many moles there are in 15.00616 mg of $\mathrm{SO}_2$:

$$n(\mathrm{SO}_2) = \frac{m(\mathrm{SO}_2)}{M(\mathrm{SO}_2)} = \frac{15.00616}{64.0638} = 0.2342 \text{ mole}$$

The molar mass of $\mathrm{SO}_2$ is:

$M(\mathrm{SO}_2) = 32.065 + 15.9994 \cdot 2 = 64.0638 \text{ g/mol}.$

So, $n(S) = n(\mathrm{SO}_2) = 0.2342$ mole.

Answer:

The number mole of S is 0.2342.