Answer to Question #240824 in Chemistry for ajajajajaj

Question

Titanium tetrachloride, TiCl4, is prepared by the reac- tion below.

3TiO2(s) + 4C(s) + 6Cl2(g) ¡

3 TiCl4(g) + 2 CO2(g) + 2 CO(g)

What is the maximum mass of TiCl4 that can be obtained from 35 g TiO2, 45 g Cl2, and 11 g C? 

Answer 1

Solution:

The molar mass of TiO₂ is 79.866 g/mol

The molar mass of Cl₂ is 70.9060 g/mol

The molar mass of C is 12.0107 g/mol

The molar mass of TiCl₄ is 189.679 g/mol

Balanced chemical equation:

3TiO₂(s) + 4C(s) + 6Cl₂(g) ⟶ 3TiCl₄(g) + 2CO₂(g) + 2CO(g)

Calculate moles of each reactant:

(35 g TiO₂) × (1 mol TiO₂ / 79.866 g TiO₂) = 0.4382 mol TiO₂

(11 g C) × (1 mol C / 12.0107 g C) = 0.9159 mol C

(45 g Cl₂) × (1 mol Cl₂ / 70.9060 g Cl₂) = 0.6346 mol Cl₂

Calculate stoichiometry coefficients:

TiO₂: (0.4382 mol / 3 ) = 0.146

C: (0.9159 mol / 4) = 0.229

Cl₂: (0.6346 mol / 6) = 0.106

As 0.106 is lowest, Cl₂ is limiting reagent and product will form according to number of moles of Cl₂.

According to stoichiometry:

6 mol of Cl₂ produces 3 mol of TiCl₄

Thus, 0.6346 mol of Cl₂ produces:

(0.6346 mol Cl₂) × (3 mol TiCl₄ / 6 mol Cl₂) = 0.3173 mol TiCl₄

Calculate the mass of TiCl₄:

(0.3173 mol TiCl₄) × (189.679 g TiCl₄ / 1 mol TiCl₄) = 60.185 g TiCl₄ = 60.2 g TiCl₄

Answer: 60.2 grams of TiCl₄