When heated, KClO3 decomposes into KCl and O2.
2KClO3⟶2KCl+3O2
If this reaction produced 23.0 g KCl, how many grams of O2 were produced?
Solution:
The molar mass of KCl is 74.55 g/mol
The molar mass of O2 is 32.00 g/mol
Balanced chemical equation:
2KClO3 ⟶ 2KCl + 3O2
According to stoichiometry:
(23.0 g KCl) × (1 mol KCl / 74.55 g KCl) × (3 mol O2 / 2 mol KCl) × (32.00 g O2 / 1 mol O2) = 14.8 g O2
Answer: 14.8 grams of O2 were produced.
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