Aqueous hydrobromic acid HBr
will react with solid sodium hydroxide NaOH
to produce aqueous sodium bromide NaBr
and liquid water H2O
. Suppose 61. g of hydrobromic acid is mixed with 38.4 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.
HBr + NaOH = NaBr + H2O
According to the equation, n (NaBr) = n (HBr) = n (NaOH).
n = m / M
M (NaBr) = 102.9 g/mol
M (HBr) = 80.9 g/mol
M (NaOH) = 40 g/mol
n (HBr) = 61 / 80.9 = 0.75 mol
n (NaOH) = 38.4 / 40 = 0.96 mol
Therefore, HBr is the limiting reactant.
n (NaBr) = n (HBr) = 0.75 mol
m (NaBr) = n x M = 0.75 x 102.9 = 77.2 g
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