calculate the mass of oxygen needed to react 10.0g of calcium to form calcium oxide
Solution:
Calculate the moles of calcium (Ca):
The molar mass of Ca is 40 g/mol
Hence,
(10.0 g Ca) × (1 mol Ca / 40 g Ca) = 0.25 mol Ca
Balanced chemical equation:
2Ca + O2 → 2CaO
According to stoichiometry:
2 mol of Ca reacts with 1 mol of O2
Thus, 0.25 mol of Ca reacts with:
(0.25 mol Ca) × (1 mol O2 / 2 mol Ca) = 0.125 mol O2
Calculate the mass of oxygen (O2):
The molar mass of O2 is 32 g/mol
Hence,
(0.125 mol O2) × (32 g O2 / 1 mol O2) = 4 g O2
Answer: 4 grams of oxygen (O2).
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