Answer to Question #231850 in Chemistry for Ruksar

Question

Calculate the energy of a photon of radiation with a wavelength of 2.67 x 10-7 m. What part of the electromagnetic spectrum will this radiation fall in?

Answer 1

Solution:

Energy of a photon:

E = h × ν

or

E = h × c / λ

where

h is Planck's constant (h = 6.626×10⁻³⁴ J ⋅ s),

c is the speed of light (c = 2.998×10⁸ m ⋅ s⁻¹),

λ is the wavelength of the radiation (λ = 2.67×10⁻⁷ m).

Therefore,

E = (6.626×10⁻³⁴ J ⋅ s × 2.998×10⁸ m ⋅ s⁻¹) / (2.67×10⁻⁷ m) = 7.44×10⁻¹⁹ J

E = 7.44×10⁻¹⁹ J

Ultraviolet (λ = 267 nm)

Answer:

E = 7.44×10⁻¹⁹ J,

ultraviolet (UV).