Answer to Question #231101 in Chemistry for Dee_Pee

Question

how will you prepare 50mills of 50 millimoles solution of potassium hydroxide and calcium hydroxide given that their molecular weight are 56.1g/mol and 74.0g/mol respectively

Answer 1

C_M = n/V

n = m/M

1) 0.05 M = n/0.05 L

n (KOH) = 0.05/0.05 = 1 mol

m (KOH) = n x M = 1 x 56.1 = 56.1 g

To prepare 50mills of 50 millimoles solution of potassium hydroxide, 56.1 g of KOH is required.

2) 0.05 M = n/0.05 L

n (Ca(OH)₂) = 0.05/0.05 = 1 mol

m (Ca(OH)₂) = n x M = 1 x 74.0 = 74.0 g

To prepare 50mills of 50 millimoles solution of potassium hydroxide, 74.0 g of Ca(OH)₂ is required.