Question #228799
You added 20g of compound Cin 125 mL water. The MW of the compound C is 285g/mol. What the final molarity of the compound in that 125mL water?
Expert's answer
СM = n/V
n = m/M
n = 20/285 = 0.07 g/mol
CM = 0.07/0.125 = 0.56 mol/L
You added 20g of compound Cin 125 mL water. The MW of the compound C is 285g/mol. What the final molarity of the compound in that 125mL water?
СM = n/V
n = m/M
n = 20/285 = 0.07 g/mol
CM = 0.07/0.125 = 0.56 mol/L
