2KClO3(s) → 2KCl(s) + 3O2(g)
According to the equation
n (KClO3) = n (KCl)
n (O2) = 3/2 x n (KClO3) = 3/2 x n (KCl)
n = m / M
M (KClO3) = 122.5 g/mol
n (KClO3) = 100 / 122.5 = 0.8 mol
n (KCl) = n (KClO3) = 0.8 mol
M (KCl) = 74.6 g/mol
m (KCl) = n x M = 0.8 x 74.6 = 60.9 g
n (O2) = 3/2 x 0.8 = 1.2 mol
n (O2) = V/22.4
V (O2) = n (O2) x 22.4 = 1.2 x 22.4 = 26.9 l
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