Answer to Question #225451 in Chemistry for merlyn

Question

When 21.3 g of CO2 are made, how much heat is released?

Answer 1

Solution:

Calculate the moles of CO₂:

The molar mass of CO₂ is 44.01 g/mol.

Therefore,

(21.3 g CO₂) × (1 mol CO₂ / 44.01 g CO₂) = 0.48398 mol CO₂ = 0.484 mol CO₂

Consider the following thermochemical reaction for kerosene:

2C₁₂H₂₆(l) + 37O₂(g) → 24CO₂(g) + 26H₂O(l) + 15026 kJ

From the thermochemical reaction equation:

15026 kJ is released when 24 mol of CO₂ is released

x kJ is released when 0.484 mol of CO₂ is released

Therefore,

x = (0.484 mol CO₂ × 15026 kJ) / (24 mol CO₂) = 303.024 kJ = 303 kJ

x = 303 kJ

Answer: 303 kJ of heat is released.