Balance the following redox reaction in basic media:
CN-
(aq) + MnO4
-
(aq) → CNO-
(aq) + MnO2
The given redox reaction is -
CN−+MnO−4→CNO−+MnO2
Oxidation half-reaction:
CN−+H2O+2OH−→CNO−+2H2O+2e−
Reduction half-reaction:
MnO−4+4H2O+3e−→MnO2+2H2O+4OH−
Multiply oxidation half-reaction by (3) and reduction half-reaction by (2), to make electron gain equivalent to electron lost,
Oxidation half-reaction:
3CN−+3H2O+6OH−→3CNO−+6H2O+6e−
Reduction half reaction:
2MnO−4+8H2O+6e−→2MnO2+4H2O+8OH−
Add both the half-reactions together and simplify the reaction to get the balanced redox reaction
3CN−+2MnO−4+H2O→3CNO−+2MnO2+2OH−
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