Answer to Question #225161 in Chemistry for Junior

Question

Calculate the mass of 0.000423 mol sodium borate, Na2B4O7.10H2O and express

the answer in milligrams. 

Answer 1

Solution:

The molar mass of Na₂B₄O₇×10H₂O is 381.37 g/mol

Therefore,

(0.000423 mol Na₂B₄O₇×10H₂O) × (381.37 g Na₂B₄O₇×10H₂O / 1 mol Na₂B₄O₇×10H₂O) = 0.16132 g

1 gram (g) is equal to 1000 milligrams (mg).

Therefore,

(0.16132 g Na₂B₄O₇×10H₂O) × (1000 mg / 1 g) = 161.32 mg Na₂B₄O₇×10H₂O

Answer: 161.32 mg Na₂B₄O₇×10H₂O