Answer to Question #223746 in Chemistry for Dan

Question

What current will deposit 3.25grams of zinc for 2 hours

Answer 1

Solution:

Faraday's law of electrolysis can be used.

Faraday's law of electrolysis can be expressed as:

m = (Q × M) / (Z × F) = (I × t × M) / (Z × F)

where:

m = mass of material (g)

M = molar mass of material (g/mol)

I = current (A)

t = time (s)

Z = number of electrons

F = Faraday constant, 96485 (C mol^-1)

Therefore,

I = (m × Z × F) / (t × M)

where:

m(Zn) = 3.25 g

Z = 2 (Zn²⁺ + 2e → Zn)

F = 96485 C mol^-1

t = (2 h) × (60 min / 1 h) × (60 s / 1 min) = 7200 s

M(Zn) = 65 g/mol

Plug in the numbers and solve for I:

I = (3.25 g × 2 × 96485 C mol^-1) / (7200 s × 65 g/mol) = 1.34 C/s = 1.34 A

I = 1.34 A

Answer: 1.34 A