Answer to Question #222784 in Chemistry for mimi

Question

K₄Fe(CN)₆3H₂O

Diagram above shows the chemical formula of potassium hexacynoferrate (II) trihydrate. What is the relative mass of this compound?

Answer 1

Solution:

K₄Fe(CN)₆∙3H₂O = potassium hexacynoferrate (II) trihydrate = K₄FeC₆N₆H₆O₃

M_r(K₄Fe(CN)₆∙3H₂O) = 4×A_r(K) + A_r(Fe) + 6×A_r(C) + 6×A_r(N) + 6×A_r(H) + 3×A_r(O)

A_r of K = 39.0983

A_r of Fe = 55.845

A_r of C = 12.0107

A_r of N = 14.0067

A_r of H = 1.00784

A_r of O = 15.999

Thus,

M_r(K₄Fe(CN)₆∙3H₂O) = 4×(39.0983) + (55.845) + 6×(12.0107) + 6×(14.0067) + 6×(1.00784) + 3×(15.999) = 422.387

M_r(K₄Fe(CN)₆∙3H₂O) = 422.387

Answer: The relative mass of K₄Fe(CN)₆∙3H₂O is 422.387