Answer to Question #222200 in Chemistry for caleb villarreal

Question

If I have 2.9 L of gas at a pressure of 5.0 atm and a temperature of 50.0 °C, what will be the new temperature if I decrease the volume of the gas to 2.4 L and decrease the pressure to 3.0 atm(round to correct sig figs)

Answer 1

pV=nRT

n = pV / RT

R = 0.082 057 46(14) L atm K⁻¹ mol⁻¹

n = 5.0 x 2.9 / (0.082 x (50 + 273)) = 0.5 mol

T = pV / nR

T2 = 3.0 x 2.4 / (0.5 x 0.082) = 175.6 K = -97.4°C