Answer to Question #222194 in Chemistry for caleb villarreal

Question

If 0.65 moles of hydrogen occupies 9.0 L, how many moles must be added to inflate the balloon to 15.6 L?(round to two sig figs)

Answer 1

n₁ = 0.65 mol

V₁ = 9.0 L

n₂ = unknown

V₂ = 15.6 L

Solution:

PV = nRT

V/n = RT/P

RT/P = const

Therefore,

V₁/n₁ = V₂/n₂

n₂ = n₁V₂ / V₁

n₂ = (0.65 mol × 15.6 L) / (9.0 L) = 1.1267 mol = 1.1 mol (two sig figs)

n₂ = 1.1 mol

Answer: 1.1 mol of hydrogen gas must be added to inflate the balloon to 15.6 L.