If a gas in a closed container is pressurized from 15.0 atm to 16.0 atm and its original temperature was 25.0 °C, what would the final temperature of the gas be (in °C)? **Hint: You still need to convert to Kelvin, then convert back to Celsius also round the answer to the correct sig figs
P1/T1 = P2/T2
T1 = 25.0 + 273 = 298.0 K
15.0/298.0 = 16.0/T2
T2 = 318.1 K
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