Answer to Question #216289 in Chemistry for Freeman

Question

0.25g of acid is titrated with 108M NaOH, if it takes 27.22ml NaOH to reach the endpoint, what is the equivalent weight of the acid

Answer 1

C_M = n / V

n = C_M x V

n = m / M

M = m / n

n (NaOH) = 0.108 x 0.02722 = 0.003 mol

M_acid = 0.25 / 0.003 = 83.3 g/mol