what mass of CH4 formed when 8.3 moles of CO react with hydrogen according to following equation?
2CO + 2H2 → CH4 + CO2
Solution:
Balanced chemical equation:
2CO + 2H2 → CH4 + CO2
According to the equation above: n(CO)/2 = n(CH4)
n(CH4) = n(CO) / 2 = 8.3 mol / 2 = 4.15 mol
The molar mass of CH4 is 16.04 g/mol.
Therefore,
(4.15 mol CH4) × (16.04 g CH4 / 1 mol CH4) = 66.566 g CH4 = 66.6 g CH4
Answer: 66.6 grams of CH4 formed.
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