Iron reacts with hydrochloric acid to produce iron (II) chloride and hydrogen gas: Fe (s) + 2 HCl (aq) → FeCl2 (aq) + H2 (g) The H2 gas from the reaction of 2.2 g of iron with excess acid is collected in a 10.0L flask at 25˚C. What is the pressure of H2 gas in this flask
Solution:
Balanced chemical equation:
Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g)
According to the equation above: n(Fe) = n(H2)
The molar mass of Fe is 55.845 g/mol.
Therefore,
(2.2 g Fe) × (1 mol Fe / 55.845 g Fe) = 0.0394 mol Fe
n(H2) = n(Fe) = 0.0394 mol
The Ideal Gas equation can be used.
The Ideal Gas equation can be expressed as: PV = nRT
P = unknown
V = 10.0 L
n = 0.0394 mol
R = 0.0821 atm L mol-1 K-1
T = 25˚C + 273 = 298 K
Thus,
P = nRT / V
P = (0.0394 mol × 0.0821 atm L mol-1 K-1 × 298 K) / (10.0 L) = 0.0964 atm
P = 0.0964 atm
Answer: 0.0964 atm is the pressure of H2 gas in this flask.
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