Question #206772

Based on the following equation what is the heat of formation, ΔHf°, for H2O(l) 


2H2(g)+O2(g)=2H2O(l)+136.6kcal


1
Expert's answer
2021-06-15T04:52:01-0400

Gives


2H2(g)+o22H2o(l)+136.6kcal2H_2(g)+o_2\rightarrow2H_2o(l)+136.6kcal

Hfr=HrHp=136.6×4.2kJ/mol∆H_fr=H_r-H_p=136.6\times4.2kJ/mol

Hfr=2×0+2×02×(285.8)∆H_{fr}=2\times0+2\times0-2\times(-285.8)

∆Hfr=571.6kJ/mol


Hfr=571.6kJ/mol×2mol=1143.2kJ∆H_{fr}=571.6kJ/mol\times2mol=1143.2kJ

Hf=1143.2KJ573.72KJ=569.48KJ∆H_{f}=1143.2KJ-573.72KJ=569.48KJ


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