Based on the following equation what is the heat of formation, ΔHf°, for H2O(l)Â
2H2(g)+O2(g)=2H2O(l)+136.6kcal
Gives
"\u2206H_fr=H_r-H_p=136.6\\times4.2kJ\/mol"
"\u2206H_{fr}=2\\times0+2\\times0-2\\times(-285.8)"
∆Hfr=571.6kJ/mol
"\u2206H_{f}=1143.2KJ-573.72KJ=569.48KJ"
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