Answer to Question #206771 in Chemistry for Rebecca Rowe

Question

14. What volume of gas will be produced when 35.0 g of calcium reacts with excess hydrochloric acid at SATP?

Answer 1

The chemical reaction between calcium and hydrochloric acid is as follows:

Ca + 2HCl = CaCl₂ + H₂

From here, the number of moles of calcium equals:

n(Ca) = m(Ca) / Mr(Ca) = 35.0 g / 40 g/mol = 0.875 mol

According to the reaction, the number of moles of calcium equals the number of moles of hydrogen produced. As a result, n(H₂) = 0.875 mol

Finally, the volume of gas is:

V(H₂) = n(H₂) × 22.41 L/mol = 0.875 mol × 22.41 L/mol = 19.6 L

Answer: 19.6 L