Answer to Question #205199 in Chemistry for Ankush

Question

Using a table of thermochemical data, calculate Enthalpy for the reaction.

CH4(g)+2O2(g)=CO2(g)+2H2O(g)

Answer 1

Given, enthalpies of formation of CH₄, CO₂ and H₂O are 74.8 kJmol^−1, −393.5 kJmol^−1, −286 kJmol^−1 respectively.

ΔH_o = ΔH_f^o_(products) − ΔH_f^o_(reactants)

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= [ΔH^o_(CO2) + ΔH^o_(H2O)] − [ΔH^o_{(CH4​)}o + 2ΔH^o_(O2​)]

= [−393.5 + 2×(−286.2)] − [−74.8+2×0] = −890.7kJ