The equation for the decomposition of mercury(II) oxide is as follows. Determine Heat of formation for HgO(s)?
2HgO(s)+182KJ=2Hg(l)+O2(g)
"2HgO(s)+182KJ=2Hg(l)+O2(g)"
So,
heat of the reaction, ∆Hrxn = +182Kj
The heart of the reaction will be
∆Hrxn =2×heat of formation of Hg(l) + heat of formation of O2(g) – (heat of formation of HgO×2)
Or, 182 Kj =2×∆Hf(Hg) + ∆Hf(O2) – ∆Hf(HgO)
Since, heat of formation of elements is zero,
So, ∆Hf(HgO) = 0 kj/mol and ∆Hf(O2) = 0 kj/mol
So, 182 Kj = 2×0 + 0 – ∆Hf(HgO)
Or, ∆Hf(HgO) = –182 Kj
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