This question is related to the equilibrium reaction below:
H2(g) + F2(g) ⇌ 2HF (g),ΔH = -542 kJmol-1
i. The following stresses are applied to the equilibrium:
1. the temperature is increased,
2. a catalyst is added,
3. the concentration of HF is reduced,
4. the volume is decreased.
1. the temperature is increased - velocity of the forward reaction goes up
2. a catalyst is added - velocity of the forward reaction goes up
3. the concentration of HF is reduced - velocity of the forward reaction goes up
4. the volume is decreased - velocity of the reverse reaction goes up
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