how many grams of Cl₂ would you need to produce 234 grams of NaCl
According to the reaction:
2Na + Cl2 = 2NaCl
From here, the mass of chlorine gas equals:
m(Cl2) = m(NaCl) × Mr(Cl2) / (Mr(NaCl) × 2) = 234 g × 71 g/mol / (58.5 g/mol × 2) = 142 g
Answer: 142 g
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