If the pOH of an aqueous NaOH solution is 11.55, what is the [H3O+] for this solution?
Solution:
NaOH is a strong base, which means that it is 100% ionized in solution:
NaOH → Na+(aq) + OH−(aq)
(pH must be greater than 7).
Therefore, most likely pH is 11.55, not pOH!!!
Assuming pH = 11.55, convert between pH and [H3O+] using the following equation:
pH = − log[H3O+]
[H3O+] = 10−pH
[H3O+] = 10−11.55 = 2.82×10−12
[H3O+] = 2.82×10−12 M
Answer: [H3O+] = 2.82×10−12 M
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