Answer to Question #200827 in Chemistry for Isaac Chibuike Isa

Question

What volume of 0.53 mol per DM cube of Potassium Hydroxide would yield 8.2 gram of potassium hydroxide in one vaporization to dryness

Answer 1

C_M = n/V

V = n / C_M

n = m / M

M (KOH) = 56.1 g/mol

n (KOH) = 8.2 / 56.1 = 0.15 mol

V (KOH) = 0.15 / 0.53 = 0.28 L = 0.28 dm³