Question

How many grams are contained in 3.5 moles of N2O7

Answer 1

Solution:

N₂O₇ - nitroperoxynitrate

The molar mass of N₂O₇ is 140.01 g/mol.

Therefore,

(3.5 mol N₂O₇) × (140.01 g N₂O₇ / 1 mol N₂O₇) = 490.035 g N₂O₇ = 490 g N₂O₇

Answer: 490 grams are contained in 3.5 moles of N₂O₇.