what volume of 3mol h2so4 is required to react with 10g of zinc
H2SO4 + Zn = ZnSO4 + H2
M (Zn) = 65.4 g/mol
n = m / M
n (Zn) = 10 / 65.4 = 0.15 mol
Acording to the equation, n (Zn) = n (H2SO4) = 0.15 mol
CM = n / V
V (H2SO4) = n / CM = 0.15 / 3 = 0.05 L
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