Question

how grams of CO22 would be formed when 76.2g of acetylene (C2H2(g)) burns completely?

Answer 1

The reaction of acetylene burning:

2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O

The acetylene molar mass is 2*12+2*1=26 g/mol The amount of acetylene is
n(C₂H₂) = m(C₂H₂)/M(C₂H₂) = 76.2 g / 26 g/mol = 2.93mol According to reaction above, the amount of CO₂ is
n(CO₂) = 2*n(C₂H₂) = 2.93*2 = 5.86 mol
The mass of CO₂ is
m(CO₂) = n(CO₂)*M(CO₂) = 5.86 mol * 44 g/mol = 257.8 g