Ammonium nitrate (NH.NO,) decomposes to yield nitrogen gas, water, and oxygen gas.
a. Write the balanced chemical reaction:
b. How many grams of water are produced when 36.0 grams of ammonium
nitrate decompose?
Solution:
Ammonium nitrate = NH4NO3
a) Balanced chemical equation:
2NH4NO3(s) → 2N2(g) + O2(g) + 4H2O(g)
b) The molar mass of NH4NO3 is 80.0 g/mol.
Therefore,
(36.0 g NH4NO3) × (1 mol NH4NO3 / 80.0 g NH4NO3) = 0.45 mol NH4NO3
According to the equation above: n(NH4NO3) = n(H2O)/2
n(H2O) = 2 × n(NH4NO3) = 2 × 0.45 mol = 0.90 mol
The molar mass of H2O is 18.0 g/mol.
Therefore,
(0.90 mol H2O) × (18.0 g H2O / 1 mol H2O) = 16.2 g H2O
Answers:
a) 2NH4NO3(s) → 2N2(g) + O2(g) + 4H2O(g)
b) 16.2 g H2O
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