According to the reaction:
CaCO3 = CO2 + CaO
From here the mass of carbon dioxide and calcium oxide produced in the reaction are:
m(CO2) = m(CaCO3) × Mr(CO2) / Mr(CaCO3) = 50 g × 44 g/mol / 100 g/mol = 22 g
m(CaO) = m(CaCO3) × Mr(CaO) / Mr(CaCO3) = 50 g × 56 g/mol / 100 g/mol = 28 g
Answer: 22 g and 28 g
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