How many grams of aluminum oxide are produced from the synthesis reaction of 30.0 g of Al
balance the equation
_ Al+ _ O2 -> _ Al2O3
Solution:
Balanced chemical equation:
4Al + 3O2 → 2Al2O3
According to the equation:
(30.0 g Al) × (1 mol Al / 26.98 g Al) × (2 mol Al2O3 / 4 mol Al) × (101.96 g Al2O3 / 1 mol Al2O3) = 56.68 g
Mass of Al2O3 = 56.68 g = 56.7 g Al2O3
Answer: 56.7 grams of aluminum oxide (Al2O3) are produced.
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