Answer to Question #195042 in Chemistry for Sofyan fadah

Question

How many moles of aluminum nitrate are obtained from the reaction of 0.75 mol of silver nitrate with a sufficient amount of aluminum?

Answer 1

Solution:

Balanced chemical equation:

Al + 3AgNO₃ → Al(NO₃)₃ + 3Ag

According to the equation above: n[AgNO₃] / 3 = n[Al(NO₃)₃]

Hence,

Moles of Al(NO₃)₃ = Moles of AgNO₃ / 3 = 0.75 mol / 3 = 0.25 mol

Moles of Al(NO₃)₃ = 0.25 mol

Answer: 0.25 mol of aluminum nitrate are obtained.