How many grams of sodium will result from the decomposition of 1.0 mole of sodium azide
Solution:
sodium azide = NaN3
Balanced chemical equation:
2NaN3(s) → 2Na(s) + 3N2(g)
According to the equation above: n(NaN3) = n(Na)
n(Na) = n(NaN3) = 1.0 mol
The molar mass of Na is 23 g/mol
Hence,
(1.0 mol Na) × (23 g Na / 1 mol Na) = 23 g Na
Answer: 23 grams of sodium (Na) will result.
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