Question #192813
115.24g of isopropyl alcohol at 20.1 degrees is mixed with 56.31g of water at 50.3 degrees after thermal equilibrium was reached, the temp was 36.5, what was the energy lost by water
Expert's answer
Q = C x m x deltaT
Cwater = 4200 J/kg°C
Q = 4200 x 0.05631 x (50.3 - 36.5) = 3264 J
