A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3) What mass of sodium hydroxide is needed to accomplish this
HClO3 + NaOH = NaClO3 + H2O
According to the equation, n (HClO3) = n (NaOH).
CM = n / V
n = CM x V
n (HClO3) = 3.86 x 25.5 = 98.43 mol
n (HClO3) = n (NaOH) = 98.43 mol
n = m /M
M (NaOH) = 40 g/mol
m (NaOH) = n x M = 98.43 x 40 = 3937.2 g
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