Answer to Question #190700 in Chemistry for john

Question

 Calculate the number of moles of Na⁺ ions in 25 g of sodium carbonate, Na₂ CO₃.

Answer 1

Solution:

Na₂CO₃ → 2Na⁺ + CO₃^2-

According to the equation above: n(Na₂CO₃) = n(Na⁺)/2

The molar mass of Na₂CO₃ is 105.9888 g/mol.

Hence,

(25 g Na₂CO₃) × (1 mol Na₂CO₃ / 105.9888 g Na₂CO₃) = 0.23587 mol Na₂CO₃

n(Na₂CO₃) = 0.23587 mol

n(Na⁺) = 2 × n(Na₂CO₃) = 2 × 0.23587 mol = 0.47174 mol Na⁺ ions = 0.472 mol Na⁺ ions

Moles of Na⁺ ions = 0.472 mol

Answer: 0.472 moles of Na⁺ ions in 25 g of sodium carbonate (Na₂CO₃).