What is the mass (grams) of 4.62x1024 in molecules of glucose (C6H12O6)
Solution:
One mole of any substance contains 6.022×1023 atoms/molecules.
Hence,
n(C6H12O6) = (4.62×1024 molecules of C6H12O6) × (1 mol / 6.022×1023 molecules) = 7.672 mol C6H12O6
The molar mass of C6H12O6 is 180.156 g/mol.
Hence,
(7.672 mol C6H12O6) × (180.156 g C6H12O6 / 1 mol C6H12O6) = 1382.15 g C6H12O6
Mass of C6H12O6 = 1382.15 g
Answer: 1382.15 grams of glucose (C6H12O6) are in 4.62×1024 molecules of glucose.
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