Question

What is the enthalpy change if 105 g of ethane is burned in a combustion reaction whose molar enthalpy of combustion is -1251 kJ/mol. *

Answer 1

n = m / M

M (C₂H₆) = 30.07 g/mol

n (C2H6) = 105 / 30.07 = 3.5 mol

delta H (C₂H₆) = - 1251 x 3.5 = -4367 kJ