What is the enthalpy change if 105 g of ethane is burned in a combustion reaction whose molar enthalpy of combustion is -1251 kJ/mol. *
n = m / M
M (C2H6) = 30.07 g/mol
n (C2H6) = 105 / 30.07 = 3.5 mol
delta H (C2H6) = - 1251 x 3.5 = -4367 kJ
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment