How many litersof 10M HCl are needed to make 4L of 0.4M solution
M1 = 10 M
V1 = unknown
M2 = 0.4 M
V2 = 4 L
Solution:
(Initial concentration) × (Initial Volume) = (Final concentration) × (Final Volume)
M1V1 = M2V2
Divide to isolate V1:
V1 = (M2V2) / (M1)
Plug in the numbers and solve for V1:
V1 = (0.4 M × 4 L) / (10 M) = 0.16 L (160 mL)
V1 = 0.16 L
Answer: 0.16 liters of 10 M HCl are needed to make 4 L of 0.4 M solution.
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