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Answer to Question #18228 in Chemistry for Sophia de Jesus
Question #18228
White Phosphorus P consist of P4 molecules it spontaneously ignites on contact with air. If there are 0.350 mole of P4 molecules. how many P4 molecules are present? What is the mass in grams of a sample? How many P atoms are present?
Expert's answer
m(P4) = 0.350 mol * 124g/mol = 43.4 g
N(P4) = 0.350 mol * 6.02 * 10^23 mol^-1 = 2.107 *10^23 molecules
n(P) = 4n(P4)
n(P) = 4*0.350 mol = 1.4 mol;
N(P) = 1.4 mol * 6.02 *10^23 mol^-1 = 8.428*10^23 atoms
N(P4) = 0.350 mol * 6.02 * 10^23 mol^-1 = 2.107 *10^23 molecules
n(P) = 4n(P4)
n(P) = 4*0.350 mol = 1.4 mol;
N(P) = 1.4 mol * 6.02 *10^23 mol^-1 = 8.428*10^23 atoms
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Comments
Dear I, there was a mistake. Not 128g/mol, but 124 g/mol: it is a molecular weight of P4 molecule (4*M(P)=4*31g/mol=124g/mol)
where did you get 128g/mol
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