What volume of dilute nitric acid of density 1.11g/mL and 19% nitric acid by weight contains in 10g nitric acid.
Solution:
nitric acid - HNO3
%HNO3 = (Mass of HNO3 / Mass of solution) × 100%
Hence,
Mass of solution = (Mass of HNO3 × 100%) / (%HNO3)
Mass of solution = (10 g × 100%) / (19%) = 52.63 g
Mass of solution = Solution volume × Density
Hence,
Solution volume = Mass of solution / Density
Solution volume = (52.63 g) / (1.11 g/mL) = 47.4 mL
Answer: 47.4 mL of dilute HNO3
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