Answer to Question #181826 in Chemistry for Decy Jae

Question

1.     How much NH₄Cl is required to prepare 100mL of a solution containing 70mg NH₄Cl per mL?

Answer 1

Solution:

70 mg NH₄Cl per 1 mL

??? mg NH₄Cl per 100 mL

Hence,

(70 mg NH₄Cl / 1 mL) × (100 mL) = 7000 mg = 7 g

Answer: 7 grams of NH₄Cl is required.