Answer to Question #180946 in Chemistry for Patricia

Question

You add 200.0 mL of 0.10 M KOH to 50.0 mL of 0.40 M HF. What is the pH of the resulting solution? Provide answer with solution.

Answer 1

KOH + HF = KF + H₂O

C_M = n / V

n = C_M x V

According to the equation, n (KOH) = n (HF).

n (KOH) = 0.10 x 0.2000 = 0.02 mol

n (HF) = 0.40 x 0.0500 = 0.02 mol

In this case, the base is completely neutralized by acid. Therefore, the resulting pH=7.